
Finding a vector
P is the point 2,3
Q is the point 6,6
Write down vector PQ in column form. I got 4 over 3 (not sure how to use latex with this one)
The question:
PQRS is a prallelogram
Vector PR (not sure how to make the vector sign in latex) = 4 over 7
Find vector QS
I did 4 over 4 + 0 over 4 and got 4 over 1 as an answer.
Correct?


Hi
Your answer is correct but I haven't understood how you got it
$\displaystyle \vec{PR} = \binom{4}{7}$
$\displaystyle \vec{PQ} = \binom{4}{3}$
$\displaystyle \vec{QS} = \vec{QP} + \vec{PR} + \vec{RS} = 2 \vec{QP} + \vec{RS} = \binom{2 \times (4) + 4}{2 \times (3) + 7} = \binom{4}{1}$

$\displaystyle \vec{QR}=\vec{PS}$
$\displaystyle \vec{PQ}=\vec{SR}=\binom{4}{3}$
Because$\displaystyle \vec{PR}=\binom{4}{7}$
$\displaystyle \vec{QR}=\binom{0}{4}=\vec{PS}$
Because$\displaystyle \vec{QS}=\vec{PQ}+\vec{PS}$
$\displaystyle \vec{QS}=\binom{4}{3}+\binom{0}{4}=\binom{4}{1}$

