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Math Help - Indices

  1. #1
    Junior Member
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    Indices

    Simplify \frac{2^{n + 2} + 8}{2^{2n} + 2^{n + 1}}
    (final answer: 2^{2 - n})
    So these are the steps that I have done:
    \frac{2^{n + 2} + 2^3}{2^{2n} + 2^{n + 1}}
    = \frac{2^{n + 2} + 2^3}{2^{2n} + 2^{n + 1}}
    = \frac{{2^n} \cdot 2^2 + 2^3}{2^{2n} + 2^n \cdot 2^1}

    I am not quite sure of what to do next. Any help would be greatly appreciated. Thank you in advance.
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  2. #2
    Senior Member Dinkydoe's Avatar
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    Write the next step as  \frac{2^2(2^n+2)}{2^{n}(2^n+2)}
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  3. #3
    Junior Member
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    Oh ok I got the answer now, thanks a lot!
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