# Indices

• Jun 5th 2010, 06:18 AM
caramelcake
Indices
Quote:

Simplify $\frac{2^{n + 2} + 8}{2^{2n} + 2^{n + 1}}$
(final answer: $2^{2 - n}$)
So these are the steps that I have done:
$\frac{2^{n + 2} + 2^3}{2^{2n} + 2^{n + 1}}$
$= \frac{2^{n + 2} + 2^3}{2^{2n} + 2^{n + 1}}$
$= \frac{{2^n} \cdot 2^2 + 2^3}{2^{2n} + 2^n \cdot 2^1}$

I am not quite sure of what to do next. Any help would be greatly appreciated. Thank you in advance.
• Jun 5th 2010, 06:22 AM
Dinkydoe
Write the next step as $\frac{2^2(2^n+2)}{2^{n}(2^n+2)}$
• Jun 5th 2010, 06:32 AM
caramelcake
Oh ok I got the answer now, thanks a lot!