So these are the steps that I have done:Quote:

Simplify $\displaystyle \frac{2^{n + 2} + 8}{2^{2n} + 2^{n + 1}}$

(final answer: $\displaystyle 2^{2 - n}$)

$\displaystyle \frac{2^{n + 2} + 2^3}{2^{2n} + 2^{n + 1}}$

$\displaystyle = \frac{2^{n + 2} + 2^3}{2^{2n} + 2^{n + 1}}$

$\displaystyle = \frac{{2^n} \cdot 2^2 + 2^3}{2^{2n} + 2^n \cdot 2^1}$

I am not quite sure of what to do next. Any help would be greatly appreciated. Thank you in advance.