1. ## complet the square

Solve by completing the square:

x^2 + 7/2x =7 (7/2x is a fraction)

2. To ind the "magic number" that will complete the square - use the formula (b/2)^2. Then add this "magic number" to both sides of the equation. After doing this, you will be able to factor the left hand side into a perfect square trinomial. Then simply take the square root of both sides and continue to solve for x. To divide a fraction by two remember to invert and multiply, then simply square the numerator (top) and the denominator (bottom). If you need more help. Let me know.

3. sorry but I am lost? I have no idea what you just said...

4. Originally Posted by bball20
Solve by completing the square:

x^2 + 7/2x =7 (7/2x is a fraction)
$\displaystyle x^2+ 2 \times \frac{1}{2}\times \frac{7}{2}x +\left(\frac{7}{4}\right)^2 - {\left(\frac{7}{4}\right)}^2 = 7$

$\displaystyle {\left( x+\frac{7}{4}\right)}^2 = 7+{\left(\frac{7}{4}\right)}^2$

5. Compare:$\displaystyle (x+ a)^2=$
$\displaystyle x^2+ 2ax+ a^2$ and
$\displaystyle x^2+ (7/2)x+ ?$

With 2a= 7/2, what is a? And then what is $\displaystyle a^2$?