3x(x-3)= -4 Help! Thanks
Follow Math Help Forum on Facebook and Google+
$\displaystyle 3x(x-3)= -4$ $\displaystyle 3x^2-9x= -4$ $\displaystyle 3x^2-9x+4= 0$ $\displaystyle a=3,b=-9,c=4$ Was that o.k?
Originally Posted by kelsikels 3x(x-3)= -4 $\displaystyle 3x^2-9x+4=0???????$
what about the second part?
Originally Posted by kelsikels what about the second part? What second part? Do you mean the complete solution? Oh no! That is your job!
Originally Posted by kelsikels what about the second part? The formula is $\displaystyle x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$ Pickslides has given you values for a, b and c
Originally Posted by pickslides $\displaystyle a=3,b=-9,c=4$ Substitute these values into $\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$
here's a graph of $\displaystyle 3x^2-9x+4= 0$ if it is of any interest the x intercepts are not as obvious as they look. as mentioned already the quadradic equation will give the intercepts
View Tag Cloud