I need to solve the system in as many ways as possible

5x + 10 y <= 600

4x + 3y <= 250

Thanks

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- Jun 2nd 2010, 10:37 AMecdino2Systems of Linear Inequalities
I need to solve the system in as many ways as possible

5x + 10 y <= 600

4x + 3y <= 250

Thanks - Jun 2nd 2010, 11:52 AMrunning-gag
Hi

You can sketch the 2 lines

5x + 10 y = 600

4x + 3y = 250

The solutions are the coordinates of the points which are simultaneously below the 2 lines