# Tranpose Formule

• Jun 2nd 2010, 10:12 AM
mcrilly
Tranpose Formule
Greetings,

I have been banging my head against a wall trying to understand how-to make 'x' the subject of the following equation:

y = (w + x) / (x - 2)

I can't figure out how to make it appear as it does on the mock exam.

So far, I have the following steps:

y(x - 2) = w + x

xy - 2y = w + x

xy - x = w + 2y

And it's here where I get stuck. I just can't get my head around getting 'x' on its own.

Regards,

Mike.
• Jun 2nd 2010, 10:15 AM
Unknown008
You got it right so far and got through all what is difficult. You only need to factorise the x.

You know that:

$2+2x = 2(1+x)$

Right? Well, do the same with x in your question, I'm sure you'll get it easily :)
• Jun 2nd 2010, 10:34 AM
mcrilly
Is it:

x(y - 1) = w + 2y?
• Jun 2nd 2010, 12:21 PM
Esthephane
Quote:

Originally Posted by mcrilly
Is it:

x(y - 1) = w + 2y?

You're almost there. You can divide the (y-1)
• Jun 2nd 2010, 03:57 PM
mcrilly
Quote:

Originally Posted by Esthephane
You're almost there. You can divide the (y-1)

x = (w + 2y) / (y - 1)

:)
• Jun 3rd 2010, 07:58 AM
Unknown008
Yup, that's it :)