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Math Help - logartimic equation

  1. #1
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    logartimic equation

    how to solve this equation?
    log (3x - 2) = 1
    thank you
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  2. #2
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    Quote Originally Posted by alessandromangione View Post
    how to solve this equation?
    log (3x - 2) = 1
    thank you
    I assume this is a natural logarithm (of base e). If not, just replace e with whatever your base happens to be...

    \log{(3x - 2)} = 1

    e^{\log{(3x - 2)}} = e^1

    3x - 2 = e

    3x = e + 2

    x = \frac{e + 2}{3}.
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  3. #3
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    i found another method...but i dont' get this method...can u explain to me? expcially how it got '10'...
    3x - 2 = 10 1 . Rewrite this log equation in exponential form. 3x - 2 = 10
    3x = 12
    x = 4
    Solve this linear equation for x.
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  4. #4
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    Quote Originally Posted by alessandromangione View Post
    i found another method...but i dont' get this method...can u explain to me? expcially how it got '10'...
    3x - 2 = 10 1 . Rewrite this log equation in exponential form. 3x - 2 = 10
    3x = 12
    x = 4
    Solve this linear equation for x.
    In that case, the base of your logarithm is 10, not e.

    Follow the same instructions as I gave you, but replace e with 10.
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