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{3x}/{(3-2x)^{2} = {A}/(3-2x) + {B}/{(3-2x)^{2} 3x = A(3-2x) + B Compare the3 coefficients to find A and B.
Originally Posted by sa-ri-ga-ma $\displaystyle \frac{3x}{(3-2x)^2}$ = $\displaystyle \frac{A}{3-2x}+\frac{B}{(3-2x)^2}$ 3x = A(3-2x) + B Compare the3 coefficients to find A and B. Thanks, got it.
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