How do I expand this?
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{3x}/{(3-2x)^{2} = {A}/(3-2x) + {B}/{(3-2x)^{2} 3x = A(3-2x) + B Compare the3 coefficients to find A and B.
Originally Posted by sa-ri-ga-ma = 3x = A(3-2x) + B Compare the3 coefficients to find A and B. Thanks, got it.
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