1. ## Solve for x

[3/(x-4)] + 5 = 7x/(x^2-x-12)

Thanks!

2. Originally Posted by windia
[3/(x-4)] + 5 = 7x/(x^2-x-12)

Thanks!
$\frac{3 + 5(x-4)}{x-4} = \frac{7x}{(x-4)(x+3)}$

(5x - 17) = 7x/(x+3)

Now simplify and solve for x.

3. Thanks!!