[3/(x-4)] + 5 = 7x/(x^2-x-12) Thanks!
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Originally Posted by windia [3/(x-4)] + 5 = 7x/(x^2-x-12) Thanks! $\displaystyle \frac{3 + 5(x-4)}{x-4} = \frac{7x}{(x-4)(x+3)}$ (5x - 17) = 7x/(x+3) Now simplify and solve for x.
Thanks!!
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