$\displaystyle d=\sqrt{\frac{3h}{2}}$ I got $\displaystyle h=\frac{2d^2}{3}$ is this correct?
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Originally Posted by Mukilab $\displaystyle d=\sqrt{\frac{3h}{2}}$ I got $\displaystyle h=\frac{2d^2}{3}$ is this correct? yes
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