given the line y=x-1 and the curve y=k(x^2)

show, by using a graphical argument or otherwise, that when k is a negative constant the equation k(x^2)=x-1 has two real roots, one of which lies between 0 and 1

this question followed a series of straightforward quadratics problems but here i'm a bit lost, i don't even know how to work it through

can someone show me?