If log5=a and log36=b, determine an expression for log in terms of a and b I can get the log5 side, as 2a, but i can't seem to get the other side, is the expression wrong, or am i just confused, i can't seem to get 36log6,
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Originally Posted by nuckers If log5=a and log36=b, determine an expression for log in terms of a and b I can get the log5 side, as 2a, but i can't seem to get the other side, is the expression wrong, or am i just confused, i can't seem to get 36log6, log36 = log(6)^2 = 2log(6) = b. So log(6) = .....?
Originally Posted by sa-ri-ga-ma log36 = log(6)^2 = 2log(6) = b. So log(6) = .....? no, i dont understand it, i have to have 36log so b=36
Originally Posted by nuckers no, i dont understand it, i have to have 36log so b=36 log(6) + log(6) = log(36) = b So 2log(6) = b Or log(6) = b/2
log(6/25) = log(6) - log(25) Using sa-ri-ga-ma's result, log(6) = b/2 Now for the other part, a = log(5) = (1/2)(2 log(5)) = (1/2)log(25) 2a = log(25) So combining,
thanks guys, but i'm just not seeing it, maybe i've just looked at too much math today, maybe a good nights sleep will make it better
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