a baseball player has three times singles as doubles with a total of 116 runs
how many singles did he have?
TR = 3s + d
can any one help!
Thanks
Ray
I get a problem when I work out your problem.
116 = s + 2d
s = 3d
So
116 = 3d + 2d = 5d
d = 116/5
which doesn't make sense since we need a whole number.
My conclusion would be that the problem has no solution.
EDIT: Ah I guess my baseball knowledge isn't very good. I thought a double counted as two runs. Haha.
This problem really brings out my ignorance of baseball, but how did you get TR = 3s + d?
It seems from this article that knowing singles and doubles doesn't actually tell you anything about how many runs the player had. Isn't it possible for a player to have 50 singles and 50 doubles and no runs, because the batters afterward always struck out?
A run, is when someone SCORES.
He may mean total BASES.
You get 2 bases when you reach second, by hitting a double.
You get one base, by hitting a single.
You get three bases by hitting a triple.
You receive four bases by hitting a homerun.
YOU only SCORE when you reach home plate.
There is no guarantee that you score when you hit anything but a homerun.
and besides Rayban being banned
what is....propleam? some kind of new rpg?