Not sure how to put this in here, so hopefully i can do my best
Please help with this
$\displaystyle log3(logx(log416))=-1$
The 3, x and 4 are all the base, so they should be lower than the log and 16. I hope that i said and did that right
Use underscore, which should be SHIFT plus the key right next to "0" and slightly above and to the right of "P" if your keyboard is like mine.
$\displaystyle log_3(log_x(log_416))=-1$
$\displaystyle log_x(log_416)=3^{-1}=\frac{1}{3}$
$\displaystyle log_416=x^{\frac{1}{3}}$
$\displaystyle 2=x^{\frac{1}{3}}$
$\displaystyle x=2^3 = 8$