Find the lenght of a side of an Equilateral Triangle with sides with the following equations;
(x+3y-8)cm
(2x+y+3)cm
(5x-y+8)cm
Thanks.
$\displaystyle x+3y-8 = 2x+y+3$
$\displaystyle x = 2y - 11$
$\displaystyle x+3y-8 = 5x-y+8$
$\displaystyle 4x = 4y - 16$
$\displaystyle x = y - 4$
$\displaystyle 2y - 11 = y - 4$
$\displaystyle y = 7$
$\displaystyle x = y - 4$
$\displaystyle x = 3$
$\displaystyle s = x+3y-8 = 3 + (3)(7) - 8 = 16\ \text{cm}$