In the diagram, take O as the centre of the circle.

P,q,R and S are points on the circle

Angle ROP=110

Calculate the angle RSP

I did 360-110

then 360-55

Then 2*(305-250)=110

rsp=110

http://i296.photobucket.com/albums/m...ab/Circles.jpg

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- May 31st 2010, 11:29 AMMukilabPoints on a circle
In the diagram, take O as the centre of the circle.

P,q,R and S are points on the circle

Angle ROP=110

Calculate the angle RSP

I did 360-110

then 360-55

Then 2*(305-250)=110

rsp=110

http://i296.photobucket.com/albums/m...ab/Circles.jpg - May 31st 2010, 11:33 AMUnknown008
The correct way to do it is to make use of angle PQR.

From the properties of angles within a circle, we know that angle 2PQR = angle ROP

Therefore, angle PQR = 110/2 = 55

Now, from quadrilaterals inscribed within a circle, the sum of two opposite angles = 180 degrees.

Therefore, 180 - 55 = RSP

And RSP = 125 degrees - May 31st 2010, 02:21 PMMukilab
Interesting, do you have a place where I can shift through all of these laws? I'm studying for an exam and I have nothing but general knowledge to draw from, not knowing half of the requirements.

- May 31st 2010, 09:39 PMnikhileasiest and correct method
its very easy

**NO****NEED TO CALCULATE ANGLE PQR**

angle PSR=(1/2)(angle POR in the major segment)

angle POR in the major segment =360-110=250

therfor

angle PSR=(1/2)*250=125

this is the easiest and shortest method - June 1st 2010, 02:28 AMMukilab
Thanks but where do you get these methods? Point me towards a website, book, anything please