How do you complete the square of $\displaystyle (-2y^2 +2yz -z^2)/2$ into the form $\displaystyle -(a((x-b)^2))/2$ Thanks Adam
Last edited by adam_leeds; Jun 1st 2010 at 02:32 AM.
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Originally Posted by adam_leeds How do you complete the square of $\displaystyle (-2y^2 +2yz -z^2)/2$ Thanks Adam $\displaystyle \frac{-2y^2 + 2yz - z^2}{2}$ $\displaystyle -\frac{y^2 + y^2 - 2yz + z^2}{2}$ $\displaystyle -\frac{y^2 + (y-z)^2}{2}$ ... that's about all i could do with it.
thanks
Any other ideas?
Originally Posted by adam_leeds How do you complete the square of $\displaystyle (-2y^2 +2yz -z^2)/2$ into the form $\displaystyle -(a((x-b)^2))/2$ Thanks Adam It cannot be put into that form. (By the way, what is x meant to be? The variables of your problem are y and z).
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