FIND OUT THE VALUE OF "X" FROM THE EQUATION GIVEN BELOW: -
x^[log a to the base 2] + a^[log x to the base 2] = 2a^2
I tried taking Log to the bast 10 to both sides, but it didn't work out. Any idea how to do it????
FIND OUT THE VALUE OF "X" FROM THE EQUATION GIVEN BELOW: -
x^[log a to the base 2] + a^[log x to the base 2] = 2a^2
I tried taking Log to the bast 10 to both sides, but it didn't work out. Any idea how to do it????