1. ## Intercepts

(1) 4x-12 = 34

Graph line use intercepts if only 1 intercept exists use it and another point to draw the line.

(2) -25X + Y = 55

What is the Y intercept

What is the X intercept

2. Originally Posted by OneidaFL
(1) 4x-12 = 34

Graph line use intercepts if only 1 intercept exists use it and another point to draw the line.

$\displaystyle 4x-12 = 34$

$\displaystyle 4x = 46$

$\displaystyle x = \frac{46}{4}$

Originally Posted by OneidaFL

(2) -25X + Y = 55

What is the Y intercept

What is the X intercept
y-intercept make x = 0

$\displaystyle -25X + Y = 55$

$\displaystyle -25\times 0 + Y = 55$

Now solve for y

x-intercept make y = 0

$\displaystyle -25X + Y = 55$

$\displaystyle -25X + 0 = 55$

Now solve for x

3. Originally Posted by OneidaFL
(1) 4x-12 = 34

Graph line use intercepts if only 1 intercept exists use it and another point to draw the line.

(2) -25X + Y = 55

What is the Y intercept

What is the X intercept
1. This is not the equation of a line.

2. To find the $\displaystyle x$ intercept, let $\displaystyle y = 0$ and solve for $\displaystyle x$.

To find the $\displaystyle y$ intercept, let $\displaystyle x = 0$ and solve for $\displaystyle y$.

4. Originally Posted by Prove It
1. This is not the equation of a line.
Or maybe the equation of a vertical line?

5. (1) Solving for x will give you your x-intercept. Since there is no y, it's obvious that this is a vertical (|) line running parallel to the x-axis.

(2)To find the x-intercept set y=0 and solve for x.

So,

$\displaystyle -25x+(0)=55$ Solve for x

To find the y-intercepts set x=0 and solve for y.

So,

$\displaystyle -25(0)+y=55$ Solve for y.

Hope that helps

6. Originally Posted by pickslides
Or maybe the equation of a vertical line?
True, but that's not what the question sounds like...

From the sound of the question, there should be an equation of the form $\displaystyle y = mx + c$, so that you can graph it either using the intercepts, or the $\displaystyle y$-intercept and gradient.

7. Originally Posted by Prove It
1. This is not the equation of a line.

Pickslides is right. It's the equation of a vertical line. You can think of y being equal to 0.

8. Originally Posted by Prove It
True, but that's not what the question sounds like...

From the sound of the question, there should be an equation of the form $\displaystyle y = mx + c$, so that you can graph it either using the intercepts, or the $\displaystyle y$-intercept and gradient.
Agreed. It does seem like a strange one to be asked.