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Math Help - Intercepts

  1. #1
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    Intercepts

    (1) 4x-12 = 34

    Graph line use intercepts if only 1 intercept exists use it and another point to draw the line.



    (2) -25X + Y = 55

    What is the Y intercept

    What is the X intercept
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  2. #2
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    Quote Originally Posted by OneidaFL View Post
    (1) 4x-12 = 34

    Graph line use intercepts if only 1 intercept exists use it and another point to draw the line.

    4x-12 = 34

    4x = 46

    x = \frac{46}{4}


    Quote Originally Posted by OneidaFL View Post

    (2) -25X + Y = 55

    What is the Y intercept

    What is the X intercept
    y-intercept make x = 0

    -25X + Y = 55

    -25\times 0 + Y = 55

    Now solve for y



    x-intercept make y = 0

    -25X + Y = 55

    -25X + 0 = 55

    Now solve for x
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  3. #3
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    Quote Originally Posted by OneidaFL View Post
    (1) 4x-12 = 34

    Graph line use intercepts if only 1 intercept exists use it and another point to draw the line.



    (2) -25X + Y = 55

    What is the Y intercept

    What is the X intercept
    1. This is not the equation of a line.

    2. To find the x intercept, let y = 0 and solve for x.

    To find the y intercept, let x = 0 and solve for y.
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    Quote Originally Posted by Prove It View Post
    1. This is not the equation of a line.
    Or maybe the equation of a vertical line?
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  5. #5
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    (1) Solving for x will give you your x-intercept. Since there is no y, it's obvious that this is a vertical (|) line running parallel to the x-axis.

    (2)To find the x-intercept set y=0 and solve for x.

    So,

    -25x+(0)=55 Solve for x

    To find the y-intercepts set x=0 and solve for y.

    So,

    -25(0)+y=55 Solve for y.

    Hope that helps
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  6. #6
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    Quote Originally Posted by pickslides View Post
    Or maybe the equation of a vertical line?
    True, but that's not what the question sounds like...

    From the sound of the question, there should be an equation of the form y = mx + c, so that you can graph it either using the intercepts, or the y-intercept and gradient.
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  7. #7
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    Quote Originally Posted by Prove It View Post
    1. This is not the equation of a line.


    Pickslides is right. It's the equation of a vertical line. You can think of y being equal to 0.
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  8. #8
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    Quote Originally Posted by Prove It View Post
    True, but that's not what the question sounds like...

    From the sound of the question, there should be an equation of the form y = mx + c, so that you can graph it either using the intercepts, or the y-intercept and gradient.
    Agreed. It does seem like a strange one to be asked.
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