How would I find... If the mean of the numbers a, b, c, d, and e is m and m is not equal to 0, then a + b + c + d + e/ m =
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Originally Posted by dnntau How would I find... If the mean of the numbers a, b, c, d, and e is m and m is not equal to 0, then a + b + c + d + e/ m = Remember that the mean is given by: $\displaystyle m = \frac{a+b+c+d+e}{5} $ Hence: $\displaystyle \frac{a+b+c+d+e}{m} = \frac{a+b+c+d+e}{\frac{a+b+c+d+e}{5}} = (a+b+c+d+e) \times \frac{5}{a+b+c+d+e} = 5 $
Thanks so much.
$\displaystyle \frac{a + b + c + d + e}{5} =m $ Find $\displaystyle \frac{a + b + c + d + e}{ m}$ $\displaystyle \frac{a + b + c + d + e}{\frac{a + b + c + d + e}{5} }$ $\displaystyle (a + b + c + d + e) \times\frac{5}{a + b + c + d + e}$ Then what?
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