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Math Help - The mean of the numbers.

  1. #1
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    The mean of the numbers.

    How would I find...
    If the mean of the numbers a, b, c, d, and e is m and m is not equal to 0, then a + b + c + d + e/ m =
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  2. #2
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    Quote Originally Posted by dnntau View Post
    How would I find...
    If the mean of the numbers a, b, c, d, and e is m and m is not equal to 0, then a + b + c + d + e/ m =
    Remember that the mean is given by:

     m = \frac{a+b+c+d+e}{5}

    Hence:

     \frac{a+b+c+d+e}{m} = \frac{a+b+c+d+e}{\frac{a+b+c+d+e}{5}} = (a+b+c+d+e) \times \frac{5}{a+b+c+d+e}  = 5
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  3. #3
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    Thanks so much.
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  4. #4
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    \frac{a + b + c + d + e}{5} =m

    Find

    \frac{a + b + c + d + e}{ m}

    \frac{a + b + c + d + e}{\frac{a + b + c + d + e}{5} }

    (a + b + c + d + e) \times\frac{5}{a + b + c + d + e}

    Then what?
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