z = (90-x)
w = (120-y)
y = (180-x)
x = (120 - v)
v = 180-(240-y)
Solve for any of them, I don't care! They all end up solving eachother..AHH is these even possible?
Ooooooooooookay then. I presume these are simultaneous?
The bottom equation is already solved for v, so substitute this into the other equations:
v = 180 - (240 - y) = y - 60
z = (90-x)
w = (120-y)
y = (180-x)
x = (120 - [y - 60]) = 180 - y
The w equation is already solved for w so substitute this into the others (which don't depend on w anyway):
v = y - 60
w = 120 - y
y = (180-x)
x = 180 - y
Again, the x equation is already solved for x so:
v = y - 60
w = 120 - y
x = 180 - y
y = (180 - [180 - y]) = y
So any value of y solves this. So your solution set is:
v = y - 60
w = 120 - y
x = 180 - y
and y is any number.
-Dan