z = (90-x)

w = (120-y)

y = (180-x)

x = (120 - v)

v = 180-(240-y)

Solve for any of them, I don't care! They all end up solving eachother..AHH is these even possible?

Printable View

- May 7th 2007, 05:32 PMstones44Big System Equations
z = (90-x)

w = (120-y)

y = (180-x)

x = (120 - v)

v = 180-(240-y)

Solve for any of them, I don't care! They all end up solving eachother..AHH is these even possible? - May 7th 2007, 06:17 PMtopsquark
Ooooooooooookay then. I presume these are simultaneous?

The bottom equation is already solved for v, so substitute this into the other equations:

v = 180 - (240 - y) = y - 60

z = (90-x)

w = (120-y)

y = (180-x)

x = (120 - [y - 60]) = 180 - y

The w equation is already solved for w so substitute this into the others (which don't depend on w anyway):

v = y - 60

w = 120 - y

y = (180-x)

x = 180 - y

Again, the x equation is already solved for x so:

v = y - 60

w = 120 - y

x = 180 - y

y = (180 - [180 - y]) = y

So any value of y solves this. So your solution set is:

v = y - 60

w = 120 - y

x = 180 - y

and y is any number.

-Dan