Originally Posted by

**Ash** Can you show me how to go about solving these problems? I'm suppose to translate the given information into a system of equations and solve the system to determine the two numbers.

#1. One number exceeds a second number by 8. Three-fourths of the larger number is 3 more than the smaller number.

With the problem #2, I want to make sure I'm doing it right.

I'm suppose to determine whether each ordered pair is a solution of the given system of linear equations.

#2 (-0.5,0)

2x+3y=3

8x=12y-4

When I plug (-0.5,0) into the equation I get

2(-0.5) + 3(0)=3

-3 = 3 ,

8(-0.5) = 12(0)-4

- 4.0 = 4

-4 = -4 ,

So would (-0.5,0) not be a solution to both equations since one 3 is negative and the other is a positive 3? I know it would of been a solution if it was -4 = -4 and the other was 3 = 3, but I'm not sure since one three is negative.