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Math Help - Completing the square

  1. #1
    Senior Member Mukilab's Avatar
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    Completing the square

    2x2 + 8x - 3 = 0

    My method:
    2((x^2+8x+16)-16)-3\longrightarrow 2((x+4)^2-16)-3 \longrightarrow 2(x+4)^2=35
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  2. #2
    MHF Contributor
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    Quote Originally Posted by Mukilab View Post
    2x2 + 8x - 3 = 0

    My method:
    2((x^2+8x+16)-16)-3\longrightarrow 2((x+4)^2-16)-3 \longrightarrow 2(x+4)^2=35
    2(x+4)(x+4)=35\ is\ 2x^2+16x+32=35

    which is 2x^2+16x-3=0



    Instead 2x^2+8x=3

    x^2+4x=\frac{3}{2}

    x^2+2(2x)+2^2-2^2=\frac{3}{2}

    (x+2)^2-4=\frac{3}{2}

    (x+2)^2-\frac{11}{2}=0

    2(x+2)^2-11=0
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