10x+5y=20 as form of y=mx+c

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- May 28th 2010, 05:46 PM #1

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- May 28th 2010, 05:57 PM #2
If the equation is

$\displaystyle 10x+5y=20$

Then

Divide both sides by 5.

$\displaystyle \frac{10x+5y}{5}=\frac{20}{5}$

Which equates to

$\displaystyle 2x+y=4$

Subtract $\displaystyle 2x$ from both sides

$\displaystyle -2x+2x+y=-2x+4$

Which equates to

$\displaystyle y=-2x+4$

- May 28th 2010, 06:17 PM #3

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