1. ## Sigma, Again.

Ooo here is what i posted earlier.
But the LaTex Post didnt help me :/.

$\displaystyle floor(\sum_{x = 1}^{L - 1} floor(x+300*2^x/7)/4)$

I understand Sigma but not the part on top of it, the 'L-1', Usually it is just one number?

Maybe someone here can walk me through it ?

2. Originally Posted by TylaYuhh
Ooo here is what i posted earlier.
But the LaTex Post didnt help me :/.
RuneScape experience formula

I understand Sigma but not the part on top of it, the 'L-1', Usually it is just one number?

Maybe someone here can walk me through it ?

Why should we have to go to a link for your problem?
Why can't you type it here?
You have been given the LaTeX link.

3. Originally Posted by TylaYuhh
Ooo here is what i posted earlier.
But the LaTex Post didnt help me :/.
RuneScape experience formula

I understand Sigma but not the part on top of it, the 'L-1', Usually it is just one number?

Maybe someone here can walk me through it ?

$\displaystyle L-1$ IS just one number.

It's saying that the $\displaystyle x$ counter goes

$\displaystyle 1, 2, 3, \dots, L - 1$, with $\displaystyle L$ being the "level you're calculating for".

4. Originally Posted by Plato
Why should we have to go to a link for your problem?
Why can't you type it here?
You have been given the LaTeX link.
Do you really think i would waste my time registering a account ( not to mention with an email address that contains my FULL name it in? ) just so someone will go to a link?
What do you think It would be a virus? Which you can't even get UNLESS you actually download it??

How can people go on a math help forum if the 1st time they post a problem (second for me because first time was correct, but not a help on the part i am stuck in.) they get mad...and say "Why should we have to go to a link for your problem."
...
I am looking for help, not accusations. I didn't type it because I do not know how to type the capital sigma sign.

5. Originally Posted by Prove It
$\displaystyle L-1$ IS just one number.

It's saying that the $\displaystyle x$ counter goes

$\displaystyle 1, 2, 3, \dots, L - 1$, with $\displaystyle L$ being the "level you're calculating for".

Lets say L was equal to 5.

Would that just mean you can replace the $\displaystyle L-1$ to a 4?

6. Originally Posted by TylaYuhh
Do you really think i would waste my time registering a account ( not to mention with an email address that contains my FULL name it in? ) just so someone will go to a link?
What do you think It would be a virus? Which you can't even get UNLESS you actually download it??

How can people go on a math help forum if the 1st time they post a problem (second for me because first time was correct, but not a help on the part i am stuck in.) they get mad...and say "Why should we have to go to a link for your problem."
...
I am looking for help, not accusations. I didn't type it because I do not know how to type the capital sigma sign.
\sum_{x = 1}^{L - 1} gives $\displaystyle \sum_{x = 1}^{L - 1}$.

7. Originally Posted by TylaYuhh
Lets say L was equal to 5.

Would that just mean you can replace the $\displaystyle L-1$ to a 4?
Yes.

Though I would say that in your code, you would specify what $\displaystyle L$ is somewhere before your sum, not actually inside it.

8. Originally Posted by Prove It
\sum_{x = 1}^{L - 1} gives $\displaystyle \sum_{x = 1}^{L - 1}$.
Thank you I will post the problem. Did i post it correctly? I don't know how to make the /4 under all of it :/

I apologize for..acting rude at 1st.

9. Originally Posted by Prove It
Yes.

Though I would say that in your code, you would specify what $\displaystyle L$ is somewhere before your sum, not actually inside it.
Oh, Okay. Thank you very much

10. You can learn to post with LaTeX.
If you don't want to, why should we help?
BTW: You response to me is really childish.

11. Originally Posted by Plato
You can learn to post with LaTeX.
If you don't want to, why should we help?
BTW: You response to me is really childish.

If I didn't want your help, I wouldn't post for it.
Please do not troll me for asking a question..which if i understand correctly, that is what these forums are for?
And how exactly was I childish?