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Math Help - Solve for X

  1. #1
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    Solve for X

    State Restrictions and solve for X.

     <br />
\frac{x}{x-1}+3=\frac{1}{x-1}-1<br />

    Restrictions: x≠1
    Answer: x = 1 = null

    Correct? If not, suggest correct answer.


    \frac{x+2}{2x-6}-\frac{3}{x-3}=\frac{3}{2}

    Restrictions: x≠3
    Answer: x = 3 = null

    Correct? If not, suggest correct answer.

    Thank you very much.
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  2. #2
    Super Member
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    Quote Originally Posted by larry21 View Post
    State Restrictions and solve for X.

     <br />
\frac{x}{x-1}+3=\frac{1}{x-1}-1<br />

    Restrictions: x≠1
    Answer: x = 1 = null

    Correct? If not, suggest correct answer.
    Unfortunately you didn't post your work ...

    If this is actually the correct question then this equation has no solution:

     \frac{x}{x-1}+3=\frac{1}{x-1}-1~\implies~\frac{x}{x-1}-\frac{1}{x-1} = -4~\implies~1\neq -4<br />

    \frac{x+2}{2x-6}-\frac{3}{x-3}=\frac{3}{2}

    Restrictions: x≠3
    Answer: x = 3 = null

    Correct? If not, suggest correct answer.

    Thank you very much.
    The common dnominator is 2x-6:

    \frac{x+2}{2x-6}-\frac{3}{x-3}=\frac{3}{2}~\implies~\frac{x+2}{2x-6}-\frac{6}{2x-6}=\frac{3}{2}

    And now go ahead!
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  3. #3
    Super Member Bacterius's Avatar
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    Hello,
    I each case, you clearly state that the answer you give for x is exactly the value that it is not allowed to take. Isn't there a problem ?
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