Can someone show me how to do this question. Thanks heaps y=x^2-3x-2 y=2x+4
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Originally Posted by GAVREED2 Can someone show me how to do this question. Thanks heaps y=x^2-3x-2 y=2x+4 so you can write: $\displaystyle y = y$ $\displaystyle x^2-3x-2 = 2x+4$ $\displaystyle x^2-3x-2 -2x-4=0$ $\displaystyle x^2-5x-6 = 0$ can you solve this quadratic equation for x?
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