How do I solve for this problem 54x^3-16=0
Last edited by mr fantastic; May 23rd 2010 at 07:11 PM. Reason: Re-titled.
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Originally Posted by sprink268 How do I solve for this problem 54x^3-16=0 Assuming $\displaystyle x$ is real... $\displaystyle 54x^3 = 16$ $\displaystyle x^3 = \frac{16}{54}$ $\displaystyle x^3 = \frac{8}{27}$ $\displaystyle x = \sqrt[3]{\frac{8}{27}}$ $\displaystyle x = \frac{\sqrt[3]{8}}{\sqrt[3]{27}}$ $\displaystyle x = \frac{2}{3}$.
Originally Posted by sprink268 How do I solve for this problem 54x^3-16=0 Solve for $\displaystyle x^3$ and then take the cube root of both sides. $\displaystyle 54x^3-16=0\implies x^3=\frac{16}{54}=\frac{8}{27}$ Thus, $\displaystyle x=\sqrt[3]{\frac{8}{27}}=\ldots$. Can you simplify this result?
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