1. ## Solve and Simplify

$\displaystyle (\frac{x^{-\frac{2}{3}}y^\frac{3}{4}}{x^\frac{1}{2}})^{-4} =$

First i would change it too: $\displaystyle \frac{1}{(\frac{x^{-\frac{2}{3}}y^\frac{3}{4}}{x^\frac{1}{2}})^{4}} =$

Is that correct? I need some more guidance.

Thanks.

2. its a sensible first step, i'd simplify the x's inside the bracket next

$\displaystyle \frac{x^{\frac{-2}{3}}}{x^{0.5}} = x^{\frac{-2}{3}-0.5} = x^{\frac{-7}{6}}$

3. Originally Posted by SpringFan25
its a sensible first step, i'd simplify the x's inside the bracket next

$\displaystyle \frac{x^{\frac{-2}{3}}}{x^{0.5}} = x^{\frac{-2}{3}-0.5} = x^{\frac{-7}{6}}$
Oh okay thanks. so $\displaystyle \frac{1}{(\frac{y^{\frac{3}{4}}}{x^{\frac{-7}{6}}})^4}$

Whats next?

4. Originally Posted by hydride
$\displaystyle (\frac{x^{-\frac{2}{3}}y^\frac{3}{4}}{x^\frac{1}{2}})^{-4} =$

First i would change it too: $\displaystyle \frac{1}{(\frac{x^{-\frac{2}{3}}y^\frac{3}{4}}{x^\frac{1}{2}})^{4}} =$

Is that correct? I need some more guidance.

Thanks.
in

Hi hydride,
multiply exponents and simplify

each term of the numerator and denominator must be raised to -4.answer will be of in termof x to a power andy to a power
example (x^2)^1/2=x 2x1/2=1 thats 2 times 1/2=1

bjh