Write an equation of the following line:

a line perpendicular to x - 2y + 3 = 0 and passing through the point (4;-1)

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- May 23rd 2010, 09:20 AMecdino2write an equation
Write an equation of the following line:

a line perpendicular to x - 2y + 3 = 0 and passing through the point (4;-1)

Thanks - May 23rd 2010, 09:29 AMharish21
The equation of the line given is: $\displaystyle x - 2y + 3 = 0 \implies y = \frac{1}{2}x + \frac{3}{2}$

thse slope of this line is $\displaystyle \frac{1}{2}$

now the equation of the line passing through (4,-1) is:

$\displaystyle y-(-1) = m (x-4)$ ; where m is the slope.

these two lines are perpendicular if the product of their slopes is -1, that is,

$\displaystyle \frac{1}{2} \times m = -1$

find m and fit it in the second equation to find the equation of the line. - May 23rd 2010, 10:55 AMdhiab
Hello

I'have another solution :

http://www.mathmontada.net/vb/upload...1274640781.jpg