c) Find the equation of the normal to the curve at the point (1,49) The slope of the tangent at x=1 is The normal is perpendicular to the tangent, hence invert and negate the tangent slope The slope of the normal is -1/45 and the normal contains the point (1,49) Hence, the normal equation at that point is How do i know the slope of the normail is -1/45?
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Originally Posted by ansonbound c) Find the equation of the normal to the curve at the point (1,49) How do i know the slope of the normail is -1/45? Because the normal is defined as being perpendicular to the tangent and for two perpendicular lines
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