Given that: 2logan = loga18 + loga ( n - 4 ) find the possible values of n. >>how do i get to logan^2 = loga 18(n-4) is it correct that 2logan = 2 logan^2 how do you get from: loga18 + loga ( n - 4 ) to logan^2 = loga 18(n-4)
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Originally Posted by ansonbound Given that: 2logan = loga18 + loga ( n - 4 ) find the possible values of n. >>how do i get to logan^2 = loga 18(n-4) is it correct that 2logan = 2 logan^2 how do you get from: loga18 + loga ( n - 4 ) to logan^2 = loga 18(n-4) I assume you mean base a. is true as it's the power law. You can simplify the RHS using the addition law: Now if the two bases are the same then the exponents must be equal. Which is a standard quadratic equation but remember that to satisfy the original domain
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