# Math Help - Quadractic equations

Hello everyone, I need help with one more question and that's using the quadractic formula to solve 16x2 + 96x + 128 = 0 and -4x2 + 28x – 48 = 0. Could someone tell me the answer to both so I can hurry and submit the assignment, I've been really waiting to see what I get on this.

2. But if we solve these equations for your assignment it wont be your work.

I suggest studying this, for $ax^2+bx+c=0$ then $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

It will give you the answer.

3. Originally Posted by pickslides
But if we solve these equations for your assignment it wont be your work.

I suggest studying this, for $ax^2+bx+c=0$ then $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

It will give you the answer.
I know, I've been studying this formula and I have been getting all kinds of things, that's why I posted the question.

Hello everyone, I need help with one more question and that's using the quadractic formula to solve 16x2 + 96x + 128 = 0 and -4x2 + 28x – 48 = 0. Could someone tell me the answer to both so I can hurry and submit the assignment, I've been really waiting to see what I get on this.
$16x^2 + 96x + 128 = 0$

divide every term by 16 ....

$x^2 + 6x + 8 = 0$

this is a factorable quadratic ... do it.

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$-4x^2 + 28x - 48 = 0$

start by dividing every term by -4 ... same song, second verse.

5. Break down the first term:
$16x^2$ compared to $ax^2$

Do you see to what the "a" term may be equal?