Use the technique of completing the square to transform the quadratic equation into the form (x+c)2 =a.

2x2 + 32x+ 12 = 0

Thanks alot guys.

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- May 20th 2010, 07:01 AMtysonrssAnother square technique...
Use the technique of completing the square to transform the quadratic equation into the form (

*x*+*c*)2 =*a*.

2*x*2 + 32*x*+ 12 = 0

Thanks alot guys. - May 20th 2010, 07:16 AMharish21
- May 20th 2010, 07:26 AMtysonrss
- May 20th 2010, 07:43 AMharish21
No.

You are left with $\displaystyle x^2+ 2\times x \times 8 + 6 = 0$.....(I)

So $\displaystyle (x+c)^2 = x^2+ 2.x.c +c^2$...(II)

if you compare I and II, you should see that c = 8.

So you need to have $\displaystyle (x+8)^2$, which is equal to $\displaystyle x^2 + 2.x.8+ 64$

now if you look at equation (I) again, you already have $\displaystyle x^2+ 2\times x \times 8 + 6 = 0$.

To make this $\displaystyle x^2+ 2\times x \times 8 + 64 = 0$,

you need to add 58 right?

so,

$\displaystyle x^2+ 2\times x \times 8 + 6 +58 -58= 0$

Now put the above equation in the form of $\displaystyle (x+c)^2=a$ - May 20th 2010, 07:55 AMtysonrss
- May 20th 2010, 08:08 AMharish21