Let x=a be a root fo the quartic polynomial P(x) = x^4 + Ax^3 + Bx^2 + Ax + 1 where (2+B)^2=/ 4A^2
Show that x=1/a is a root
So we have.
In order forto be defined, we cannot have
. Setting
we see that the above equation reduces to
, so we can safely say that
.
Notice that.
Multiply both sides byto remove fractions.
Look familiar?
I'm still shaky on the restriction, which seems unnecessary. I'll look into it but maybe someone with keener insight can elucidate. Or perhaps it's just unnecessary.
Ive pretty much got that. But the only thing i dont understand is that if we multiply a^4 to the polynomial, it changes dosent it. Since a^4 is not a roots of unity. Or are we to argue that since a^4 P(1/a) = 0 then p(1/a) = 0 via division?
The restriction of (2+B)^2 =/=4A^2 is i think unncessary. Think that is another part of the question.