Well we have two consecutive integers, which means that the larger number is equal to the smaller number plus one. If we let the smaller number equal , we can write

which might be the same as what you wrote, except that you should have written parentheses around (x+1).

This is not a very complicated problem; multiply through by 6 (which is the least common multiple of 2 and 3) to get

Does it look more solvable now?