Now use the logarithms as exponents to the base e. You'll get a quadratic equation. Keep in mind that this equation is only valid for x > 3
graph f(x)=ln(x) and -f(x-3)+2 by using transformations. Explain the relationship between the solutions to the original equation and the points of intersection on your graph.
How do you graph -f(x-3)+2?
please help Idon't understand the problem. thanks!
2. f(x-3) means the graph of f is translated by 3 units to the right.
3. -f(x-3) means the translated graph is refelcted about the x-axis.
4. -f(x-3) + 2 means the translated and reflected graph is translated by 2 units upwards.
5. The x-coordinate of the point of intersection is the solution to the equation above: