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Math Help - Basic Alg Help

  1. #1
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    Basic Alg Help

    I guess this is easy for you guys but i'm just confused..Please help me...

    Factor out the GCF x(3x-1) + 5(3x-1)
    *The GCF is 3x-1 so we'll divide both terms by the GCF


    x(3x-1) + 5(3x-1)
    -----------------------------------------------
    3x-1

    *cancel the 3x-1 on the x part then the 3x-1 on the 5 part leaving:

    x+5
    The complete answer then is (3x-1) (x+5)..

    I'm confused because where did 3x-1 came from I mean besides the fact that it's the GCF..Is there a rule that states that the "other set of term" will be the GCF???plss help me...
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  2. #2
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    Quote Originally Posted by quantumie View Post
    I guess this is easy for you guys but i'm just confused..Please help me...

    Factor out the GCF x(3x-1) + 5(3x-1)
    *The GCF is 3x-1 so we'll divide both terms by the GCF


    x(3x-1) + 5(3x-1)
    -----------------------------------------------
    3x-1

    *cancel the 3x-1 on the x part then the 3x-1 on the 5 part leaving:

    x+5
    The complete answer then is (3x-1) (x+5)..

    I'm confused because where did 3x-1 came from I mean besides the fact that it's the GCF..Is there a rule that states that the "other set of term" will be the GCF???plss help me...
    Let's just simplify it a bit. Imagine you had:
    xa + 5a
    GCF is a, so you "factorise" it out - you can't just "cancel" it out.
    So:
    xa + 5a = a(x+5)

    You can't say that xa + 5a = x+5 because it doesn't.
    Replace a with 3x-1 in your problem.
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  3. #3
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    tnx a lot =)
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