Find a simple formula which defines the nth term of a sequences whose first few terms are the same as those given: 1, -4, 9, -16 I already know the answer is -(-1)^n * n^2 But how would I show working out?
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$\displaystyle 1, -4, 9, -16, \dots =1^2, -2^2, 3^2, -4^2, \dots =-(-1)^1\times 1^2, -(-1)^2\times 2^2, -(-1)^3\times $ $\displaystyle 3^2, -(-1)^4\times 4^2, \dots $
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