# Thread: 2 more that seem overly simple to me

1. ## 2 more that seem overly simple to me

Find Y

-2x -y = 2
5x+2y=-3

Write an equation in std form

(-3,5) (5,3)

Thanks as always
For some reason I struggle on things that should be easy.

2. Originally Posted by ColoMath
Find Y
-2x -y = 2
5x+2y=-3

Write an equation in std form
(-3,5) (5,3)...
Hi,

multiply the 1rst equation by 2 and then add:

-4x - 2y = 4
5x + 2y = -3
--------------
x = 1 Substitute this value into the 1rst equation:

-2*1 - y = 2
-y = 4
y = -4

I assume that you are looking for the equation of a straight line passing through these two points:

(y - 5)/(x- (-3)) = (3 - 5)/(5 - (-3)) = (-2)/(8) = -1/4 that is the slope of the line:

y - 5 = -1/4*(x+3)
y - 5 = -1/4*x - 3/4

y = -1/4*x + 17/4

3. Originally Posted by earboth
Hi,

multiply the 1rst equation by 2 and then add:

-4x - 2y = 4
5x + 2y = -3
--------------
x = 1 Substitute this value into the 1rst equation:

-2*1 - y = 2
-y = 4
y = -4

I assume that you are looking for the equation of a straight line passing through these two points:

(y - 5)/(x- (-3)) = (3 - 5)/(5 - (-3)) = (-2)/(8) = -1/4 that is the slope of the line:

y - 5 = -1/4*(x+3)
y - 5 = -1/4*x - 3/4

y = -1/4*x + 17/4
Awesome, thank you

4. Originally Posted by earboth

I assume that you are looking for the equation of a straight line passing through these two points:

(y - 5)/(x- (-3)) = (3 - 5)/(5 - (-3)) = (-2)/(8) = -1/4 that is the slope of the line:

y - 5 = -1/4*(x+3)
y - 5 = -1/4*x - 3/4

y = -1/4*x + 17/4
Is that Standard form? I think that's the slope intercept form.

5. Originally Posted by ColoMath
Is that Standard form? I think that's the slope intercept form.
the equation of a line in standard form is ax + by = c, where a, b and c are real numbers. it looks better if they are integers.

so we have y = -1/4*x + 17/4

move x to one side and multiply through by 4, we get:

x + 4y = 17