Carlos has scores 83,74,81,and 85 on his past test.Find the minimum score he can make on the final exam to pass the course with average of 75 or higher, given that the final exam counts as 3 tests.
I see your point, but you do need to divide by 7. Look at this easy example. Let's say you have two tests and you made an 80 on one and a 90 on the other. Let's say the second test, the one you made a 90 on, though is worth two test grades. Here's how you would calculate your average.Originally Posted by DenMac21
$\displaystyle \frac{(80+2*90)}{n}$, where n is the number of 100 point tests. Now according to your logic I should divide by two, since there were two tests. That would give $\displaystyle \frac{(80+90+90)}{2}=130$ Oops! That can't be possible. Now let's say you divide it by three. $\displaystyle \frac{(80+90+90)}{3}=86.67$.
In the OP's question you should treat the weighted test as three separate ones compared to the max point value of the others.
Wikipedia link on weighted mean
Following this:
$\displaystyle
\frac{83 \times 1 + 74 \times 1 + 81 \times 1 + 85 \times 1 + x \times 3}{1 + 1 + 1 + 1 + 3}
$
Doing the math...
$\displaystyle
\frac{323 + x}{7}
$
Am I right?
As a side note, does anyone know if LaTeX math has the "curly x symbol with a stroke over it" which should be infront of this answer?