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Math Help - calculating grade

  1. #1
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    help with this ..

    Carlos has scores 83,74,81,and 85 on his past test.Find the minimum score he can make on the final exam to pass the course with average of 75 or higher, given that the final exam counts as 3 tests.
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  2. #2
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    Quote Originally Posted by Panaboy
    Carlos has scores 83,74,81,and 85 on his past test.Find the minimum score he can make on the final exam to pass the course with average of 75 or higher, given that the final exam counts as 3 tests.
    Carlos' final score will be calculated as follows:

    (83 + 74 + 81 + 85 + x + x + x)/7

    so you must solve for x, the equation:

    (83 + 74 + 81 + 85 + 3x)/7 = 75
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  3. #3
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    Quote Originally Posted by MathGuru
    Carlos' final score will be calculated as follows:

    (83 + 74 + 81 + 85 + x + x + x)/7

    so you must solve for x, the equation:

    (83 + 74 + 81 + 85 + 3x)/7 = 75
    Why dividing with 7 when there are 5 tests totally?

    I think it should be
    (83 + 74 + 81 + 85 + 3x) / 5 >= 75
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  4. #4
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    Quote Originally Posted by DenMac21
    Why dividing with 7 when there are 5 tests totally?

    I think it should be
    (83 + 74 + 81 + 85 + 3x) / 5 >= 75
    I see your point, but you do need to divide by 7. Look at this easy example. Let's say you have two tests and you made an 80 on one and a 90 on the other. Let's say the second test, the one you made a 90 on, though is worth two test grades. Here's how you would calculate your average.

    \frac{(80+2*90)}{n}, where n is the number of 100 point tests. Now according to your logic I should divide by two, since there were two tests. That would give \frac{(80+90+90)}{2}=130 Oops! That can't be possible. Now let's say you divide it by three. \frac{(80+90+90)}{3}=86.67.

    In the OP's question you should treat the weighted test as three separate ones compared to the max point value of the others.
    Last edited by Jameson; January 13th 2006 at 02:52 PM.
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  5. #5
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    Look at it from this perspective.

    Say we don't know what is the maximum points that can be scored on each test. So, you don't know that on fifth (final) test the maximum points is bigger then on other tests.
    Would you then divide with 7 or 5?
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  6. #6
    dud
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    Weighted mean, isn't it?

    Wikipedia link on weighted mean


    Following this:
    <br />
\frac{83 \times 1 +  74 \times 1 + 81 \times 1 + 85 \times 1 + x \times 3}{1 + 1 + 1 + 1 + 3}<br />
    Doing the math...
    <br />
\frac{323 + x}{7}<br />
    Am I right?

    As a side note, does anyone know if LaTeX math has the "curly x symbol with a stroke over it" which should be infront of this answer?
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  7. #7
    Grand Panjandrum
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    Do you mean: \bar x?

    RonL
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  8. #8
    dud
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    Excellent, thanks!
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