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Math Help - standard form

  1. #1
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    standard form

    I do not understand the process of standard form
    could someone please tell me how to write:

    64000 in standard form

    and

    64 x 10^(-7) in standard form

    and a little explanation if possible because i cannot get my head around it

    thanks
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  2. #2
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    I think standard form is just AX^2 + BX + C
    so the standard form of 64000 is
    0X^2 + 0X + 64000
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  3. #3
    Grand Panjandrum
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    Quote Originally Posted by wahhdoe View Post
    I do not understand the process of standard form
    could someone please tell me how to write:

    64000 in standard form

    and

    64 x 10^(-7) in standard form

    and a little explanation if possible because i cannot get my head around it

    thanks
    Not having your text or lecture notes I have no way of knowing what "standard form" means here. The most likely case is it is a number written with one digit before the decimal point multiplied by a power of 10.

    So:

    64000=6400.0 \time 10=640.00 \times 10^2= 64.000 \times 10^3=6.4000 \times 10^4

    The last term on the right would in this case be standard form (you may or may not want to lose the trialling zeros depending on if they are significant or not)

    In the second case you want to move the decimal point one place to the left which increases the power of 10 by 1 to give 6.4 \times 10^{-6}.


    CB
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