# standard form

• May 15th 2010, 10:04 AM
wahhdoe
standard form
I do not understand the process of standard form
could someone please tell me how to write:

64000 in standard form

and

64 x 10^(-7) in standard form

and a little explanation if possible because i cannot get my head around it

thanks
• May 15th 2010, 10:19 AM
obesechicken13
I think standard form is just AX^2 + BX + C
so the standard form of 64000 is
0X^2 + 0X + 64000
• May 15th 2010, 10:09 PM
CaptainBlack
Quote:

Originally Posted by wahhdoe
I do not understand the process of standard form
could someone please tell me how to write:

64000 in standard form

and

64 x 10^(-7) in standard form

and a little explanation if possible because i cannot get my head around it

thanks

Not having your text or lecture notes I have no way of knowing what "standard form" means here. The most likely case is it is a number written with one digit before the decimal point multiplied by a power of $\displaystyle 10$.

So:

$\displaystyle 64000=6400.0 \time 10=640.00 \times 10^2= 64.000 \times 10^3=6.4000 \times 10^4$

The last term on the right would in this case be standard form (you may or may not want to lose the trialling zeros depending on if they are significant or not)

In the second case you want to move the decimal point one place to the left which increases the power of $\displaystyle 10$ by $\displaystyle 1$ to give $\displaystyle 6.4 \times 10^{-6}$.

CB