Four consecutive odd integers are added.If the smalles integer is 2m-1, then how can the sum be represented in terms of m?
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Every 2nd number is an odd number.
Thus (2m - 1) is the first number.
(2m - 1 + 2) -> 2nd number
(2m - 1 + 4) -> 3rd number
(2m - 1 + 6) -> 4th number
The sum of all 4 these numbers are:
8m + 8
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