$\displaystyle \frac{3-x^5}{4} = \frac{2}{x} - \frac{x^5}{4}
$
common denominator is $\displaystyle 4x$ ...
$\displaystyle \frac{x(3-x^5)}{4x} = \frac{8}{4x} - \frac{x^6}{4x}$
note that $\displaystyle x \ne 0$
numerators form the equation ...
$\displaystyle x(3-x^5) = 8 - x^6$
finish it.