1. ## Simple Functions Question

I've solved a function to this answer:

$\displaystyle x^2-2x-kx+4=0$

How would you convert the above into $\displaystyle ax^2+bx+c$ format?

I've tried it like this

For bx: I've tried converting -2x-kx into $\displaystyle -x(2+k)$ by taking -x common, but that's not giving me the right roots.

What am I doing wrong? What's the rule here to form bx?

Thanks!

2. What are the conditions for the roots.
Since k is unknown, roots will be in terms of k.

3. Originally Posted by unstopabl3
I've solved a function to this answer:

$\displaystyle x^2-2x-kx+4=0$

How would you convert the above into $\displaystyle ax^2+bx+c$ format?

I've tried it like this

For bx: I've tried converting -2x-kx into $\displaystyle -x(2+k)$ by taking -x common, but that's not giving me the right roots.

What am I doing wrong? What's the rule here to form bx?

Thanks!
What you have is certainly correct: $\displaystyle x^2- 2x- kx+ 4= x^2- (2+k)x+ 4$.

4. If this is correct then for the discriminant formula a, b and c would be:

a= 1
b= -(2+k) or -2-k
c= 4

Right?