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Math Help - Simple Functions Question

  1. #1
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    Cool Simple Functions Question

    I've solved a function to this answer:

    x^2-2x-kx+4=0

    How would you convert the above into ax^2+bx+c format?

    I've tried it like this

    For bx: I've tried converting -2x-kx into -x(2+k) by taking -x common, but that's not giving me the right roots.

    What am I doing wrong? What's the rule here to form bx?

    Thanks!
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  2. #2
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    What are the conditions for the roots.
    Since k is unknown, roots will be in terms of k.
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  3. #3
    MHF Contributor

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    Quote Originally Posted by unstopabl3 View Post
    I've solved a function to this answer:

    x^2-2x-kx+4=0

    How would you convert the above into ax^2+bx+c format?

    I've tried it like this

    For bx: I've tried converting -2x-kx into -x(2+k) by taking -x common, but that's not giving me the right roots.

    What am I doing wrong? What's the rule here to form bx?

    Thanks!
    What you have is certainly correct: x^2- 2x- kx+ 4= x^2- (2+k)x+ 4.
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  4. #4
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    Cool

    If this is correct then for the discriminant formula a, b and c would be:

    a= 1
    b= -(2+k) or -2-k
    c= 4

    Right?
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