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Math Help - Richter scale

  1. #1
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    Richter scale

    Hi!

    I would really appraciate som help with this following problem. My apologies if this is en the wrong thread but im a swede and my english terms in mathematics isn't all that great :P

    Now for the task:

    <br />
M = 2/3(log10E-4.4) <br />
    M is the magnitude and E the energy which is released during and earthquake.

    > Solve this equation with respect to E..

    > A powerful earthquake has the magnitude 8.0 on the Richterscale. How much energy i released in such an earthquake?

    I've started with this one:
     8.0 = 2/3(log10E-4.4)
    12 = log10E-4.4
    16.4 = log10E

    and now im stuck


    Any help regarding these two tasks would be great

    Best Regards
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  2. #2
    Junior Member BobBali's Avatar
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    Log10E = 16.4<br />
 Log10E = Log 16.4 Take log of the other side of the equation

    E = Log16.4/Log10[/tex]

    E = 1.2148

    Hope it helps.
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  3. #3
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    thank you for the quick reply!

    I thought this was the next step but i got confused regarding the result.

    Isn't it to small? 1.21... Joule sounds very little when it supposed to be a big earthquake?

    thx again
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  4. #4
    MHF Contributor

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    BobBall was thinking that your "log10E" was "logarithm of 10 times E" when I think you meant " log_{10}E, the "logarithm, base 10, of E".

    So from log_{10}E= 16.4 use the inverse logarithm ( 10^x on a calculator to get 25118864315095801, approximately.
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