Sorry to trouble fellow forumers again with this indices question: Without using a calculator, evaluate 6^x, given that 3^(x+1) multiply by 2^(2x+1) = 2^(x+2). Thanks in advance!
Follow Math Help Forum on Facebook and Google+
Originally Posted by AeroScizor Sorry to trouble fellow forumers again with this indices question: Without using a calculator, evaluate 6^x, given that 3^(x+1) multiply by 2^(2x+1) = 2^(x+2). Thanks in advance! $\displaystyle 3^x*3*2^{2x}*2 = 2^x*2^2$ $\displaystyle 3^x*3*2^x*2 = 2^2$ $\displaystyle 6^x*6 = 4$ Now find the answer.
Originally Posted by sa-ri-ga-ma $\displaystyle 3^x*3*2^{2x}*2 = 2^x*2^2$ $\displaystyle 3^x*3*2^x*2 = 2^2$ $\displaystyle 6^x*6 = 4$ Now find the answer. Hi Sa-ri-ga-ma, you can use the command \times ($\displaystyle \times$) to output the nice multiplication symbol
View Tag Cloud